NECO 2019 EXPO Physics Practical Questions And Answers

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1a)
water passes through a dam, and into a river below. The more water that passes through a
dam, the more energy is produced. Once a dam is
built, an artificial man-made lake is created behind the dam. Electricity is produced by a device called a turbine.
Turbines contain metal coils surrounded by magnets. When the magnets spin over the metal coils, electricity is produced. Turbines are located inside dams. The falling water spins the magnets.
1b)
Given:
M=10
U=?
V=mu
F=+5cm
V=10u(virtual image)
using the real is positive convention
1/f=1/u+1/v
1/5=1/u-1/10u
1/5=10-1/10u
1/5=9/10u
10u=45
u=45/10
u=4.5cm
the object must be placed 4.5cm from the microscope.
===========
10a)
i)Mercury dropped on glass from droplets because the cohesion of mercury is stronger than it adhesion
ii)Water rise in capillary tube because the force of adhesion at water molecules with glass is greater than their cohesion to each other.
10b)
Surface tension, the ability of water to behave an elastic skin make it possible for an insect to crawl on water
============================
9a)
i)cross sectional area of plates
ii)distanace between plates
9b)
Given:
M=6kg
D=3m
G=6.67*10^-11 Nm^2kg^-2
using:
F= Gm^2/d^2
F= 6.667*10^-11*6^2/3^2
F= 2.668*10^-10N
===========
6a)
the incident ray, the reflected ray and the normal at the point of incidence all lie in the same plane
6b)
i)diverging lens
ii)the diverge light rays entering the eye from a distance object and make them appear to be coming from the person far point
===========================
7a)
ii)used as a shaving mirror
given
object distance U =13cm
image distance V = -4cm
focal length F = ?
Using the real is positive convention
1/f=1/u+1/v
1/f=1/13-1/4
1/f=4-13/52
1/f= -9/52
f= -52/9= -5.8cm
=========================
2)
the distance covered S by a body with initail speed U and final speed V in time t is
distance = average speed x time
S = (u+v/2)t
first equation
acceleration = change in velocity/time
a=v-u/t
v-u=at
v=u+at
putting the first equation into S = (u+v/2)t we have
S = (u+u+at/2)t
S = (2u+at/2)t
S = (u+at/2/2)t
S = ut+1/2at^2
this is the second equation
=========================
===============
6a). The incident ray, reflected ray and normal at the point of incidence all lie on the same plane
6b i) myopia can be corrected by placing a suitable concave or diverging lens in front of the eye
ii) the action of the lens is to diverge the light rays entering the eye from a distant object and make them appear coming from the persons far Point
===========
13a)
Specific heat capacity can be defined as the quantity of heat required to raise a unit mass of a material by one kelvin(k) or degrees Celsius(‘C)
13aii)
i)change in temperature of phase/State
ii)Change in resistance and in colour.
13aiii)
i)Linear expansivity results to expansion of metals or concrete bridges.
ii)It as well causes cracking of glass cup when hot water is poured into the glass cup.
13b)
i)Heat is nothing but the amount of energy in a body. As against this, temperature is something that measures the intensity of heat.
ii)Heat measures both kinetic and potential energy contained by molecules in an object. On the other hand, temperature measures average kinetic energy of molecules in substance.
iii)The main feature of heat is that it travels from hotter region to cooler region. Unlike temperature, which rises when heated and falls when cooled.
13ci)
when an inflated ballon is pierced and eleased, it obeys newton’s third law of motion. Air rushes out from the pierced hole and the balloon moves in the opposite direction
13cii)
Jet
13d)
using MxCxD@ =MyCyD@y
Given D@x =D@y=(25-20)=5degree
Cx=1/2CY
then Mx[1/2CY]=MYCY
Mx/My=Cy/1/2Cy
Mx/My=2
Ratio of mass Of X to Y is 2:1
===========
14a)
The law of reflection state that the angle which the incident ray makes with the normal is equal to the angle which the reflected ray makes to the same normal.
14b)
i)Effect of density
ii)Effect of temperature:- In a gas.
14c)
14d)
using the lens formula
1/f=1/u+1/v
1/5=1/6+1/v
1/5-1/6=1/v
6-5/30=1/v
1/30=1/v
V=30cm (image distance from lens)
Total distance between image of len And image of mirror is
=30+12+16
=48cm
(2a)
In a tabular form:
Under tita°:
75, 65, 55, 45, 35
Under MO(cm):
1.1, 2.0, 2.5, 3.4, 3.9
Under NO(cm):
6.2, 6.4, 6.6, 6.8, 7.2
Under H=MO/NO:
0.177, 0.313, 0.379, 0.500, .542
Under Costita:
0.2588, 0.4226, 0.5736, 0.7071, 0.8192
(2axiii)
From the graph
Slope, S =Δcostita/^ΔH
= 0.75-0.45/0.5-0.3
= 0.3/0.2
=1.5
(2axiv)
(i) I ensured both the object and the pins were in straight lines so as to avoid error due to parallax.
(ii) I made sure there was no air interference
(2bi)
Snell’s law of refraction states that the ratio of the sine of angle of incidence to the sine of the angle of refraction is a constant for a given pair of media.
I.e Sini/sinr = Π
Where Π is known as refractive index.
(2bii)
Given refractive index of glass = 1.5
i.e aΠg = 1.5(from air to glass)
SinC/sin90 = gΠa
SinC/Sinn90 = 1/aΠg
SinC/1 = 1/1.5
SinC= 0.6667
C = sin^-1(0.6667)
Critical angle for glass C = 42°
====================================================
(3a)
(ii) Vo = 2.00v
(3av)
In a tabular form
Under S/N
1, 2, 3, 4, 5
Under R(ohms):
2, 3, 4, 5, 6
Under V(v):
2.10, 2.30, 2.40, 2.50, 2.60
Under R^-1:
0.500, 0.333, 0.250, 0.200, 0.167
Under V^-1(v^-1):
0.476, 0.435, 0.417, 0.400, 0.385
3vii Slope, = Δv^-1/ΔR-1
= 0.5 – 0.355/0.6 – 0
= 0.145/0.6
S = 0.242
Intercept, C = 0.355v^-1
(3aviii)
K = S/C
K = 0.242/0.355
K = 0.68
(3ix)
(i) I ensured tight connections.
(ii) I ensured clean terminals.
(3bi)
(i) Temperature of wire
(ii) Cross sectional area of wire
(iii) Length of wire
(iv) Nature of wire
(3bii)
Draw the diagram
Effective E.m.f = 2v(parallel connection)
Effective internal resistance
= r * r/r + r = r/2ohms
Current, I , 0.8A
External resistance R = 2A
Using,
E = I(R+r)
2 = 0.8(2+r/2)
2.5 = (2+r/2)
2.5 – 2 = r/2
0.5 = r/2
r = 0.5*2 = 1ohms

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